.05x^2=2x-0.3

Solution for .05x^2=2x-0.3 equation:

.05x^2=2x-0.3

We move all terms to the left:

.05x^2-(2x-0.3)=0

We get rid of parentheses

.05x^2-2x+0.3=0

a = .05; b = -2; c = +0.3;
Δ = b2-4ac
Δ = -22-4·.05·0.3
Δ = 3.94
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{3.94}}{2*.05}=\frac{2-\sqrt{3.94}}{0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{3.94}}{2*.05}=\frac{2+\sqrt{3.94}}{0.1}
$